(6x^2-2x+5)=(2x^2-7x-11)=

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Solution for (6x^2-2x+5)=(2x^2-7x-11)= equation: 



(6x^2-2x+5)=(2x^2-7x-11)=

We move all terms to the left:

(6x^2-2x+5)-((2x^2-7x-11))=0

We get rid of parentheses

6x^2-2x-((2x^2-7x-11))+5=0



We calculate terms in parentheses: -((2x^2-7x-11)), so:

(2x^2-7x-11)

We get rid of parentheses

2x^2-7x-11

Back to the equation:

-(2x^2-7x-11)



We get rid of parentheses

6x^2-2x^2-2x+7x+11+5=0

We add all the numbers together, and all the variables

4x^2+5x+16=0

a = 4; b = 5; c = +16;
Δ = b2-4ac
Δ = 52-4·4·16
Δ = -231
Delta is less than zero, so there is no solution for the equation

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